What famil(y)ies of the periodic table is/are being investigated in this experiment?
Halogens AND Alkaline earth metals
Use the following chemical equation to answer the following question
X2 + 2Y 1 minus ----> 2X 1 minus + Y2
What species is being reduced?
X2
In solubility test section of the experiment you will be determining the solubility of various alkaline earth salts. What anions will you be using for your solubility test?
SO4 2 minus, IO3 minus, C2O4 2 minus and CO3 2 minus
In a test tube you add 2 mL of saturated chlorine water (Cl2) followed by about 1 mL of an organic solvent such as heptane (or cyclohexane). The test tube is shaken and you notice that the heptane layer has a yellow color. To this mixture you then add 1 mL of 0.1 M N a I. After shaking you notice a color change from yellow to purple in the heptane layer. What can you conclude about Cl and I from this experiment?
Information: Cl2 is pale yellow; I2 is purple; I minus (N a I) and Cl minus (N a Cl) are colorless.
Hint: For A2 + 2 B 1 minus ---> B2 + 2 A 1 minus
If a reaction occurs, A is more active than B.
If a reaction does not occur, B is more active than A.
Cl is more active than I because Cl2 reacted with I minus to form I2 and Cl minus
Ex.
By sholanejo on Brainly, https://brainly.com/question/15720257
The organic compounds (heptane/cyclohexane) will get dissolve in Cl₂ water forming a yellow colored solution.
When NaI is added into it, the following reaction between NaI and Cl2 takes place;
Cl₂ + NaI ⇒ I₂ + NaCl
In above reaction, oxidation state of Cl is getting reduced from 0 in Cl2 to -1 in NaCl.
Therefore, Cl2 is getting reduced and acting as an oxidizing agent in the reaction. While I⁻ is getting oxidised annd acting as a reducing agent.