Results for for Determination of a Chemical Formula SD Flashcards


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created 8 months ago by BerryJamJam
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general chemistry i lab
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1

a) Mass of hydrated sample? (Show work with short verbal descriptions of numbers. For example, Mass of Crucible with Hydrate - Mass of crucible = 23.40 g - 18.40 g = 5.00 g.)

b) Mass of dehydrated sample? (Show work with short verbal descriptions of numbers.)

Mass of hydrated sample: Mass of Crucible with Hydrate - Mass of crucible = 30.4855 g - 29.6900 g = 0.7955 g

Mass of dehydrated sample: Mass of Crucible with Dehydrated Sample - Mass of crucible = 30.2723 g - 29.6900 g = 0.5823 g

2

a) Mass of copper? (Show work with short verbal descriptions of numbers.)

b) No. of moles of copper? (Show work with short verbal descriptions of numbers.)

Mass of copper: Mass of Watch Glass and Copper - Mass of Empty Watch Glass = 45.9014 g - 45.7930 g = 0.1084 g

No. of moles of copper: Mass of Copper x (1 mol Cu / 63.546 g CU) = 0.1084 g x (1 mol Cu / 63.546 g CU) = 0.001705 mol Cu

3

a) Mass of water evolved? (Show work with short verbal descriptions of numbers.)

b) No. of moles of water? (Show work with short verbal descriptions of numbers.)

Mass of water evolved: Mass of Hydrated Sample - Mass of Dehydrated Sample = 0.7955 g - 0.5823 g = 0.2132 g

No. of moles of water: Mass of Water x (1 mol water / 18.016 g water) = 0.2132 g x (1 mol water / 18.016 g water) = 0.01183 mol water

4

a) Mass of chlorine in sample (by difference)? (Show work with short verbal descriptions of numbers.)

b) No. of moles of chlorine? (Show work with short verbal descriptions of numbers.)

Mass of chlorine in sample (by difference): Mass of Dehydrated Sample - Mass of Copper = 0.5823 g - 0.1084 g = 0.4739 g

No. of moles of chlorine: Mass of Chlorine x (1 mol chlorine / 35.453 g chlorine) = 0.4739 g x (1 mol chlorine / 35.453 g chlorine) = 0.01337 mol chlorine

5

a) Mole ratio, chlorine:copper in sample? (Show work with short verbal descriptions of numbers.)

b) Mole ratio of water:copper in hydrated sample? (Show work with short verbal descriptions of numbers.)

Mole ratio, chlorine:copper in sample: (Number of moles of Chlorine / Number of moles of Copper) = (0.01337 mol Chlorine / 0.001705 mol Cu) = 7.842 = (8:1)

Mole ratio of water:copper in hydrated sample: (Number of moles of Water / Number of moles of Copper) = (0.01183 mol Water / 0.001705 mol Cu) = 6.938 = (7:1)

6

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5% = 6

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