A student finds that a hydrate sample that initially has a mass of 1.6646 grams releases 0.4059 grams of water. What is the percentage of water in this hydrate? Express with the units % in the units box.
0.4059 / 1.6646 x 100 = 24.38%
A hydrate has the formula F e (NO3)3 dot 4 H2O. What is the percentage of water in this hydrate? Express with units of % in the units box.
H - 1.01 x 8 = 8.08
O - 16.00 x 4 = 64
8.08 + 64 = 72.08
Fe - 55.85 x 1 = 55.85
N - 14.01 x 3 = 42.03
O - 16.00 x 9 = 144
55.85 + 42.03 + 144 = 241.88 + 72.08 = 313.96
72.08 / 313.96 x 100 = 22.96%
During the heating of the crucible, at what distance (in inches) should the ring support be from the Bunsen burner?
- 4-5
- 5-6
- 6-7
- 3-4
- 1-2
4-5
How many times will the crucible with the hydrate sample be heated and weighed?
- 1
- 2
- 3
- 4
- 5
3