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IGCSE Maths

front 1

Find the HCF

back 1

Use tree diagram to find the product of prime numbers, (do factors and when prime number circle it) multiply the common ones from each number.

front 2

Find the LCM

back 2

Use tree diagram to do prime factorisation then multiply all the ones together without repeating from both numbers.

front 3

Recurring decimal to fraction

back 3

write x = recurring decimal, times both sides by ten. then take away 1x to remove the recurring decimal numbers and be left with the whole number. then simplify.

front 4

natural numbers

back 4

positive whole numbers, starting from 1.

front 5

integers

back 5

whole numbers (positive, zero and negative)

front 6

rational and irrational numbers

back 6

Rational numbers can be expressed as a fraction where both sides are integers, but irrational numbers can't.

front 7

reciprocal

back 7

a number that is found by dividing 1 by that number

front 8

∈

back 8

element is in set

front 9

∉

back 9

element isn't in set

front 10

∅

back 10

The empty set

front 11

A ⊆ B

back 11

A is a subset of B

front 12

A ⊈ B

back 12

A is not a subset of B

front 13

A ∪ B

back 13

all elements that are in either set A, or set B, or both

front 14

A ∩ B

back 14

The elements in both sets, intersection of Venn diagram

front 15

recall of squares and their corresponding roots from 1 to 15

back 15

1 = 12

4 = 22

9 = 32

16 = 42

25 = 52

36 = 62

49 = 72

64 = 82

81 = 92

100 = 102

121 = 112

144 = 122

169 = 132

196 = 142

225 = 152

front 16

recall cubes from 1 to 15

back 16

1 = 13

8 = 23

27 = 33

64 = 43

125 = 53

216 = 63

343 = 73

512 = 83

729 = 93

1000 = 103

front 17

What are the 6 laws of indices? 7

back 17

  1. When multiplying indices with the same base, add the powers.
  2. When dividing indices with the same base, subtract the powers.
  3. When there is a power outside the bracket multiply the powers.
  4. x to the power of 0 = 1
  5. When the index is negative, put it over 1 and flip (write its reciprocal) to make it positive x-m = 1/xm
  6. When the index is a fraction, the denominator is the root of the number or letter, then raise the answer to the power of the numerator. xa/b =( b√x)a
  7. A value raised to the power of ½ means take the square root and a value raised to the power of ⅓ means take the cube root and so on.

front 18

Simple interest

back 18

PRT/ 100

principal (original amount) x interest rate x time / 100

front 19

Compound interest

back 19

P(1 + r/100)n

Principal( 1 + rate/100)number of years

front 20

Exponential growth and decay

back 20

P(1+r)n and. P(1-r)n

principal (original amount) (1+rate)number of years etc.

front 21

Frequency density

back 21

Frequency / class width

front 22

Acceleration

back 22

Speed difference / time

front 23

Area of sector of a circle and sector length

back 23

area = (percentage of circumference x area of circle) xo /360 x π x r2

Sector length = (percentage of circumference x circumference ) x0 / 360 x 2π x r

front 24

Circle theorems

back 24

front 25

How to do differentiation and the notation that stands for it

back 25

The original formula only tells you the amount (height, profit, distance, etc.) at a point.
The rate of change tells you how fast that amount is increasing or decreasing at that point, it is the gradient and if you know x and want to find the gradient you sub this into the equation.

dy/dx

front 26

Different types of curves based off equations

back 26

front 27

Calculate percentage increase or decrease.

back 27

Value change / initial value x 100

front 28

Calculate using reverse percentages

back 28

  1. Identify the known value and the percentage it represents: For example, if a sale price is $81, and it represents a 10% discount, then $81 is 90% of the original price.
  2. Convert the percentage to a decimal or fraction: In the example above, 90% is 0.90 or 9/10.
  3. Divide the known value by the decimal or fraction: $81 / 0.90 = $90, or $81 / (9/10) = $90.
  4. The result is the original amount: The original price of the item was $90.

front 29

Rationalise the denominator.

back 29

You remove any square roots (surds) from the denominator by multiplying the entire fraction (numerator and denominator) by the surd in the denominator.

For denominators with a sum or difference of surds (e.g., a + b√c), you multiply by the same expression with the opposite sign (the conjugate) to use the difference of squares formula (a² - b²) and eliminate the surd.

Example with a rational number and a surd e.g., 1 / (√5 + √2)

  1. Identify the conjugate: The conjugate of √5 + √2 is √5 - √2.
  2. Multiply by the conjugate: (1 * (√5 - √2)) / (√5 + √2) * (√5 - √2)).
  3. Expand and simplify:
    • Numerator: √5 - √2.
    • Denominator: (√5)² - (√2)² = 5 - 2 = 3.
  4. Final answer: (√5 - √2) / 3.

front 30

how to solve quadratic simultaneous equations

back 30

When don't know value of y:

For y = x + 3

and y = x2 + 5x -2

Then once have x sub and find y. 2 answers for quadratic equation.

When know: multiply equation to make coefficients the same. then take them away for each other to find one value. sub this value into the original to find the other. 2x + 2y = 6 from 2x + 3y = 7 would result in (2x - 2x) + (3y - 2y) = 7 - 6, or y = 1

front 31

how to solve regular simultaneous equations

back 31

1. Find x or y

2. sub into other equation

3. solve

front 32

rules for linear equality graphs.

back 32

Broken lines are used to represent greater or lesser than but not equal (<, >) and straight lines for greater or lesser and equal (⩽, ⩾).

shading is used to represent unwanted regions

front 33

How to identify and solve linear, quadratic, cubic and exponential sequences.

back 33

Exponential sequences increase by a common ratio from term to term, with the nth term being defined as

a × r(n−1) where a is the first term and r is the value that you multiply by each time.

Patterns in linear sequences are recognizsd by identifying a constant difference between consecutive terms. First part is difference x n and then figure out what you have to add or minus to make it correct.

For quadratic (nth term = an2 + bn + c ) equal second difference) The coefficient of the n2 term of a quadratic sequence is half of the second difference. Then subtract this from the original sequence and you will have a regular linear equation to solve and make up the rest of the equation.

For cubic (equal third difference) nth term = an3 + bn2 + cn + d first find the third difference. The coefficient for the n3 term is the third difference divided by 6. Take this away and you will be left with a quadratic equation and second difference, solve this for the n2 coefficient and subtract. Then solve the linear and put it together.

front 34

graphs for sin, cos and tan and finding other solutions

back 34

front 35

Express direct and inverse proportion in algebraic terms

back 35

∝ is symbol for proportion. k is used for the constant.

Direct proportion = a∝ kb

Inverse proportion = The statement a is inversely proportional to b is written:

a ∝ 1/b then to solve replace 1 with the constant.

front 36

how to calculate Gradient

back 36

Gradient = rise ÷ run (or change in y ÷ change in x)

front 37

For a quadratic function how to sketch a graph and find turning point.

back 37

If coefficient of x2 is positive, the graph will be a positive U-shaped curve and vice versa.

Find y and x intercepts by making x and y 0 in the equation.

Find the turning point by either: using the equation x = -b/2a from the equation. This gives x and to find y sub value of x in original equation. If a is positive it is a min point, and if negative then max point. The original equation is y = ax2 + bx + c.

or complete the square to form a(x+p)2 + q where the coordinate are (-p, q)

front 38

How to complete the square

back 38

y = ax2 + bx + c style equation. say for y = x2 - 8x + 13.

Half the b quantity (-8) and make a bracket (x - 4)2 this makes everything match the above equation but the -42 = 16 which needs 3 take off it to become 13. so the final equation is (x - 4)2 - 3

front 39

For a recipricoral function how to sketch a graph and find the asymptotes

back 39

standard form equation is y = a/x + q

when a is negative the graph will be top left and bottom right and vice versa.

The graph will intercept x if q is not equal to 0. To find the x intercept make y = 0 and find for x in the above equation.

One asymptote is the y axis and the other is equal to y = q

front 40

maxima and minima and stationary points on a cubic graph

back 40

at stationary point dy / dx = 0 so differentiate the equation to find its new version and sub y for zero to find the values for x.

front 41

how to find stationary points on a cubic graph

back 41

at stationary point dy / dx = 0 so differentiate the equation to find its new version and sub y for zero to find the values for x. then sub x into original equation to find y.

front 42

second differential when finding max and min points on a cubic graph

back 42

first differentiate once, then do it a second time to find the new equation. Into the new equation sub the stationary point value for x and if it is positive it is the minimum point.

The function for differentiating twice is d2y / (dx)2 .

front 43

order of composite functions

back 43

if gf(x) then find for f first then g.

for a function the domain is anything that can become x and the range is what the answer range can be.

front 44

how to find difference of a line segment and the midpoint of a line segment

back 44

the midpoint is found by finding the mean of x and y. add the x coordinates together and divide by 2 to find the new x coordinate and same for y.

front 45

how to find the equation of a perpendicular bisector of a line

back 45

First find the midpoint of the line the (midpoint is found by finding the mean of x and y).

Then find the slope of the line with the formula y2 - y1 / x2 - x1 .

To find the gradient of the bisecting line calculate the negative reciprocal (when you swap numerator and denominator) so 3/2 becomes -2/3.

Sub all this into the y = mx + c formula. we have the gradient and the x and y coordinates of the point it goes through. and solve to find c. then you have the entire equation.

front 46

Find the gradient and equation of a straight line parallel

back 46

The gradient is the same as they are parallel and you are given the x and y coordinates it passes through.

Sub all this into the y = mx + c formula. (the gradient and the x and y coordinates) and solve to find c. then you have the entire equation.

front 47

acute, obtuse and reflex angles

back 47

Acute - below 90

Obtuse - between 90 and 180

Reflex - between 180 and 360

front 48

similar vs congruent

back 48

Congruent shapes are identical in both shape and size, meaning one can be perfectly superimposed on the other, while similar shapes have the same shape but can differ in size.

front 49

rhombus • parallelogram • trapezium.

back 49

Rhombus All four sides are of equal length, Both pairs of opposite sides are parallel, Opposite angles are equal, and It is a type of parallelogram.

Parallelogram

  • Opposite sides are parallel.
  • Opposite sides are equal in length.
  • Opposite angles are equal.
  • Examples of parallelograms include rhombuses, squares, and rectangles.

Trapezium (Trapezoid) Has four sides, Has exactly one pair of parallel sides, and The non-parallel sides are called legs.

front 50

prism and cuboid

back 50

a 3D shape with two identical, parallel ends (the bases) and a constant cross-section throughout its length

a cubbies is any 3d shape with 6 faces like a cube but it can be a rectangle etc.

front 51

frustum

back 51

the shape created when the top part of a cone or pyramid is cut off by a plane parallel to its base, leaving a solid with two parallel bases

front 52

parts of circle

• chord

• major and minor arc

• sector

• segment.

back 52

front 53

Draw nets.

cubes, cuboids, prisms and

pyramids

back 53

For a cylinder : The length of the rectangle is equal to the circumference of the circles. The width of the rectangle is equal to the height of the cylinder.

For a pyramid : The perpendicular height of each triangle is equal to the slant height of the pyramid.

front 54

The relationship of similar shapes lengths, surface areas and volumes of similar solids.

back 54

k is used to depict scale scale factor.

Lengths are related by the scale factor (k), areas by k², and volumes by k³.

k = length A / length B

k2 = area A / area B

k3 = volume A / Volume B

and when converting between them.

front 55

how to calculate the sum of interior angles on a polygon and therefore each individual angle

back 55

For any polygon with n sides, the sum of its interior angles is calculated with the formula (n - 2) × 180°. For a regular polygon, you can then find each interior angle by dividing the sum by n.

front 56

m3 to L

back 56

1m3 = 1000L

same as ml

front 57

find the surface area and volume of a frustum.

back 57

V = (πh/3)(R² + Rr + r²), where h is the height, R is the radius of the larger base, and r is the radius of the smaller base.

The total surface area is the sum of the areas of the two circular bases and the curved lateral surface: A = πL(R + r) + πR² + πr², where L is the slant height.

front 58

The ambiguous case

back 58

The ambiguous case is identified when the side opposite the known angle is shorter than the other known side. This means it can swing like a pendulum and form 2 triangles so there are 2 possible answers for the angle you are finding.

The ambiguous case, which can arise when using the sine rule with two sides and a non-included angle, requires checking for two possible solutions for an angle, one acute and one obtuse, by considering their sum with the given angle.

front 59

Calculate the magnitude of a vector

back 59

front 60

For a vector if given A and B find AB

back 60

To find PQ P subtract the values of the coordinates of from the coordinates of Q because you start at P and want to get to Q.

front 61

show that 3 points are collinear

back 61

front 62

show that vectors are parallel

back 62

Vectors are parallel if one is a scaler multiple of each other. eg A = k x B with k being the multiple. similar to collinear but this is between three points.

front 63

sample space

back 63

front 64

two-way tables

back 64

front 65

Identify the modal class from a grouped frequency distribution.

back 65

find the class interval with the highest frequency.

front 66

Estimate and interpret the median, percentiles, quartiles and interquartile range from cumulative frequency diagrams.

back 66

A horizontal line is drawn from the calculated median, Q1 or Q3 position on the cumulative frequency (y-axis) to intersect the cumulative frequency curve.

front 67

Calculate with frequency density on a histogram

back 67

On histograms, the vertical axis is labelled ‘Frequency density’.

frequency density = frequency ÷ class width.

front 68

When you know two sides and the included angle calculate area of triangle

back 68

Area = ½ * a * b * sin(C)

  • the two sides of the triangle are ('a' and 'b').

front 69

area of trapezium

back 69

1/2 x (upper length + lower length) x height