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Lab 10//11: Chromosomal & Genetic Disorders

front 1

Two parents are carriers of cystic fibrosis.
What are the genotype and phenotype ratios for their children?

back 1

Parents: Ff × Ff

Punnett Square:

  • FF = 25%
  • Ff = 50%
  • ff = 25%

Genotype ratio: 1 FF : 2 Ff : 1 ff
Phenotype ratio:

  • 75% unaffected
  • 25% affected (ff)
  • 50% carriers

front 2

A carrier father and an unaffected, non-carrier mother have children.
What is the probability their child will:

  • be a carrier?
  • have cystic fibrosis?

back 2

Parents: Ff × FF

Offspring:

  • 50% Ff (carriers)
  • 50% FF (unaffected)

Chance of CF: 0%
Chance of being a carrier: 50%

front 3

A carrier mother and an affected father have a child.
What are the chances their child will:

  • have sickle cell disease?
  • be a carrier?

back 3

Parents: Ss (carrier) × ss (affected)

Offspring:

  • 50% Ss (carrier)
  • 50% ss (affected)

Chance affected: 50%
Chance carrier: 50%

front 4

Two carriers for sickle cell have children.
What are the genotype ratios and phenotype ratios?

back 4

Parents: Ss × Ss

Punnett Square:

  • SS = 25%
  • Ss = 50%
  • ss = 25%

Phenotype:

  • 25% normal
  • 50% carriers
  • 25% sickle cell disease

front 5

A carrier father and an affected mother have children.
What percent will have PKU?

back 5

Parents: Pp × pp

Offspring:

  • 50% Pp (carrier)
  • 50% pp (PKU)

Probability affected: 50%

front 6

A carrier mother and a homozygous father have children.
What fraction will be carriers?

back 6

Parents: Pp × PP

Offspring:

  • 50% Pp (carriers)
  • 50% PP (normal)

Fraction carriers: 50%

front 7

A heterozygous father and a mother with normal digits have a child.
What percentage of their children will have polydactyly?

back 7

Parents: Pp × pp

Offspring:

  • 50% Pp (polydactyly)
  • 50% pp (normal)

Probability of polydactyly: 50%

front 8

A homozygous dominant mother and a normal father have children.
What percent of their children will have the polydactyly trait?

back 8

Parents: PP × pp

Offspring:

  • 100% Pp → 100% polydactyly

front 9

A heterozygous father and a normal mother have children.
What are the chances a child will inherit Huntington’s?

back 9

Parents: Hh × hh

Offspring:

  • 50% Hh (affected)
  • 50% hh (normal)

Chance of Huntington’s: 50%

front 10

Two parents, one heterozygous and one homozygous dominant, reproduce.
What percentage of their children will be affected with Huntington's disease?

back 10

Parents: Hh × HH

Offspring:

  • 50% HH (affected)
  • 50% Hh (affected)

100% of children will have Huntington’s

front 11

A carrier mother and a normal father have children.
Determine the probability for each:

  • sons with hemophilia
  • sons who are carriers
  • daughters with hemophilia
  • daughters who are carriers

back 11

Parents: XᴴXʰ (carrier) × XᴴY (normal father)

Sons:

  • 50% XʰY → hemophilia
  • 50% XᴴY → normal

Daughters:

  • 50% XᴴXʰ → carriers
  • 50% XᴴXᴴ → normal

front 12

An affected male and a normal female have children.
What are the phenotypes of all sons and daughters?

back 12

Parents: XʰY (affected male) × XᴴXᴴ (normal female)

Sons:

  • 100% XᴴY → normal

Daughters:

  • 100% XᴴXʰ → carriers

No affected children.

front 13

A colorblind father and a carrier mother have children.
What are the chances for:

  • colorblind sons
  • colorblind daughters?

back 13

Parents: XᶜY (colorblind father) × XᴺXᶜ (carrier mother)

Sons:

  • 50% XᶜY → colorblind
  • 50% XᴺY → normal

Daughters:

  • 50% XᴺXᶜ → carriers
  • 50% XᶜXᶜ → colorblind

front 14

A normal father and a carrier mother have children.
What percentage of children will be colorblind?

back 14

Parents: XᴺY × XᴺXᶜ

Sons:

  • 50% XᶜY → colorblind
  • 50% XᴺY → normal

Daughters:

  • 50% carriers (XᴺXᶜ)
  • 0% affected

Overall % colorblind children: 25%

front 15

A carrier mother and an unaffected father have children.
What percent of sons will have DMD?
What percent of daughters will be carriers?

back 15

Parents: XᴰXᵈ (carrier mother) × XᴰY

Sons:

  • 50% XᴰY → normal
  • 50% XᵈY → DMD

Daughters:

  • 50% XᴰXᵈ → carriers
  • 50% XᴰXᴰ → normal

front 16

An affected male and a carrier female have children.
What percentage of:

  • sons will have DMD?
  • daughters will have DMD?

back 16

Parents: XᵈY (affected father) × XᴰXᵈ (carrier mother)

Sons:

  • 50% XᵈY → DMD
  • 50% XᴰY → normal

Daughters:

  • 50% XᴰXᵈ → carriers
  • 50% XᵈXᵈ → affected

front 17

What chromosomal disorder is shown in the image?

back 17

Down Syndrome (Trisomy 21)

front 18

What chromosomal disorder is shown in the image?

back 18

Edward's Syndrome (Trisomy 18)

front 19

What chromosomal disorder is shown in the image?

back 19

Patau Syndrome (Trisomy 13)

front 20

What chromosomal disorder is shown in the image?

back 20

Turner Syndrome (XO)

front 21

What chromosomal disorder is shown in the image?

back 21

Klinefelter Syndrome (XXY)

front 22

What chromosomal disorder is shown in the image?

back 22

Jacob's Syndrome (XYY)

front 23

A patient comes back with karyotype of trisomy of the 23rd pair. What disorder(s) can they have?

back 23

Klinefelter Syndrome (XXY) or Jacob's Syndrome (XYY)

front 24

A patient comes back with a karyotype of monosomy of the 23rd pair. What disorder(s) can they have?

back 24

Turner Syndrome (XO)