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51 notecards = 13 pages (4 cards per page)

Viewing:

Ch.12

front 1

What are the requirements for an enzyme with Michaelis-Menten kinetics?

back 1

• Steady-state assumption: [ES] remains constant (loss
balances formation).
• [S] binds [E] to form [ES].
• Product formation is irreversible

front 2

What are the 3 ways of interpreting KM

back 2

• Substrate concentration [S] at which at enzyme is at
half its maximum velocity Vmax (much like KD at half
ligand saturation).
• Approximation of the dissociation constant.
• The ratio of the rate constants:

k-1+k2/ k1

front 3

What is a turnover number?

back 3

• Turn over number: kcat = Vmax/[E]total
The turnover number is a metric for the rate at which
substrate is converted to product (turnover) unique to
each enzyme.

front 4

What is the catalytic efficiency of an enzyme?

back 4

• Catalytic efficiency: kcat/KM
Catalytic efficiency scores an enzyme based on both its
affinity for substrate and rate of catalysis

front 5

Enzyme kinetics seeks to determine the initial and maximal reaction velocity that enzymes can

back 5

attain and the binding affinities for substrates and inhibitors

front 6

Michaelis-Menten equation has a ______line on a graph

back 6

non-linear

front 7

Bisubstrate reactions can occur by _____or______mechanisms or by a _______mechanism

back 7

ordered, random-sequential, Ping-pong

front 8

1st order reactions display a linear plot of the

back 8

substrate or product concentration, as a function of time

front 9

Rate law is the mathematical relationship

back 9

between the reaction rate or velocity, and concentration of reactions (linear)

front 10

The amount of A consumed per unit of time

back 10

rate, or velocity

front 11

Formula for rate law

back 11

v=k[A]number in front of letter

front 12

Michaelis-Menten formula:

back 12

vo=Vmax[S]/ Km+[S]

front 13

Vo is equal to

back 13

the slope

front 14

At low [S], the rate is proportional

back 14

as in a first-order reaction

front 15

At high [S], the enzyme reaction approaches

back 15

zero-order kinetics :Vo=Vmax

front 16

Rate of formation of ES is _____, while rate of dissociation is ___.

Rate of product formation is ____

back 16

k1, k-1, k2

front 17

Catalysis is limiting, because the rate is independent of [S](E is saturated

back 17

0th order (when Kmis less than)

front 18

Rate is dependent on [S], [S] is limiting

back 18

1st order (when Km is greater than)

front 19

When above Km, it starts to

back 19

plateau due to saturation increasing

front 20

Vmax=k2[ET]

back 20

no data

front 21

Km=(k-1+k2)/k1

back 21

no data

front 22

Small Km means

back 22

little dissociation (10-6)

front 23

Larger Km means

back 23

lots of dissociation (10-2)

front 24

Kcat, the turnover number, is the number of

back 24

substrate molecules converted to product per enzyme molecules, per unit of time, when E is saturated with substrate

front 25

Catalytic efficiency formula:

back 25

kcat/Km

front 26

kcat/Km is approaching

back 26

1.0x109

front 27

At temperatures are above 50o to 60oC,

back 27

enzymes typically decline in activity

front 28

The two classes of single-displacement:

back 28

random and ordered

front 29

Random single displacement where either

back 29

substrate may bind first, followed by the other substrate

front 30

Ordered single displacement where a

back 30

leading substrate binds first, followed by the other substrate

front 31

Double displacement (Ping-Pong) reactions

back 31

involves a covalent intermediate

front 32

In single displacement, high concentrations the

back 32

y-intercept is lower

front 33

Random, single-displacement reaction is formed rapidly and reversibly when

back 33

enzyme is added to a reaction mixture containing A,B,P, and Q

front 34

Ordered, single-displacement reaction leading substrate (A) must

back 34

bind first, followed by B. And for the products, P and Q

front 35

Double-displacement has a formation

back 35

of a covalently modified enzyme intermediate, E'

front 36

Reversible inhibitor may bind

back 36

at the active site or at some other site

front 37

Four types of reversible enzyme inhibitors:

back 37

-competitive

-noncompetitive

-mixed noncompetitive

-uncompetitive

front 38

Competitive inhibition

back 38

only time where inhibitor can be competed by the substrates

front 39

Increases the apparent Km but

back 39

no effect on Vmax

front 40

Noncompetitive inhibitor

back 40

decreases Vmax with no change in Km

front 41

Mixed noncompetitive alters

back 41

both Km and Vmax

front 42

Uncompetitive inhibition alters

back 42

both Km and Vmax but with same slope Km/Vmax

front 43

Uncompetetive inhibition only observed

back 43

in enzyme having two or more substrates

front 44

What type of reversible inhibitor is this?

back 44

Competitive Inhibition

front 45

Competitive inhibition______apparent Km but______on Vmax

back 45

increases, no effect

front 46

What type of reversible inhibitor is this?

back 46

Pure noncompetitive inhibition

front 47

Pure noncompetitive inhibition____Vmax with ____in Km

back 47

decreases, no change

front 48

What type of reversible inhibitor is this?

back 48

Mixed noncompetitive inhibition

front 49

Mixed noncompetitive inhibition alters Km and Vmax by _____

back 49

decreasing

front 50

What type of reversible inhibitor is this?

back 50

Uncompetitive inhibition

front 51

Uncompetitive inhibition alters both Km and Vmax but have ______

back 51

the same slope, Km/Vmax