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Exercise 45: Principles of Heredity

front 1

Actual genetic makeup

back 1

Genotype

front 2

Chromosomes determining malesness/femaleness

back 2

Sex Chromosomes

front 3

situation in which an individual has identical alleles for a particular trait

back 3

Homozygons

front 4

genes not expressed unless they are present in homozygous condition

back 4

recessive

front 5

Expression of a genetic trait

back 5

phenotype

front 6

Situation in which an individual has different alleles making up his genotype for a particular trait

back 6

heterozygous

front 7

genes for the same trait that may have different expressions

back 7

alleles

front 8

chromosomes regulating most body characteristics

back 8

autosomes

front 9

The more potent gene allele: masks the expression fo the less potent allele

back 9

dominant

front 10

In humans, farsightedness is inherited by possession of a dominant allele (A). If a man who is homozygous for normal vision (aa) marries a woman who is heterozygous for farsightedness (Aa), what proportion of their children would be expected to be Farsighted? _____%

back 10

If the man is aa he can donate a or a to his child. The woman can donate A or a. So the possibilities are: Aa, Aa, aa, aa

So 50% of the time they'll be Aa, 50% aa. Farsightedness is Aa, so 50%

front 11

A metabolic disorder call phenylketonuria (PKU) is due to an adnormal recessive gene (p). Only homozygous recessive individuals exhibit this disorder. What percentage of the offspring will be anticipated to have PKU if the parents are Pp and pp? _____%

back 11

The possibilities are: Pp, Pp, pp, pp so the answer is: 50%

front 12

A man obtained 32 spotted and 10 solid color rabbits from a mating of two spotted rabbits. Which trait is dominant? Recessive? what is the probable genotype of the rabbit parents? _____x_____

back 12

Spotted is dominant (there are more of them occuring in the same mating pair)
Recessive is solid.
genotype of parents: Ss X Ss

front 13

Assume that that allele controlling brown eyes (B) is dominant over that controlling blue eyes (b) in humans. A blue eyed man marries a brown eyes woman and they have six children, all brown eyed. What is that most likely genotype of the father? of the Mother? If the seventh child had blue eyes what could you conclude about the parents genotype?

back 13

Father: bb
Mother: BB
The only way to produce a child with blue eyes is bb. This would not be possible then since only the father has a b allele.

Blue eyes child, you can conclude: If the seventh child had blue eyes, the mother must have a b allele as well, so the father would be bb and the mother would have to be Bb.

front 14

Tail length on a bobcat is controlled by incomplete dominance. The alleles are (T) for normal tail length and (t) for tail-less
What name could/would you give to the tails of heterozygous (Tt) cats?
How would their tail length compare with that of TT or tt bobcats?

back 14

For this one since TT is a normal tail and tt is tail-less, Tt would produce a short tail since its inbetween the two.

Example: Since this is incomplete dominance, there is "blending" for instance if RR was a red flower, and rr was a white flower, Rr would make a pink flower.

front 15

If curly-haird individuals are genotypically CC, strait-haired are cc, and wavy haired individuals are heterozygotes (Cc), what percentage of various phenotypes would be anticipated from a cross between a CC woman and a cc man?
curly?_____ % wavy_______? strait_______?

back 15

Curly: 0%
Wavy: 100%
Straight: 0%

front 16

What does it mean when someone says a particular characteristic is sex-linked?

back 16

It is carried on the F(X) sex chromosome

front 17

You are a male and you have been told that hemophilia "runs in your genes" whose ancestors, your mother's or your father's should you investigate? Why?

back 17

Moms because males can only receive the X chromosome from their mothers, the fathers contribution is always Y

front 18

An (XC)(Xc) female marries and (Xc)(Y) man:
What is the probability of producing a color blind son?
A color blind daughter?
A daughter who is a carrier for the color-blind allele?

back 18

Well the key to this problem is that color blind is recessive, so little c. The mother is a carrier.
So they could have either a daughter who is a carrier (XC)(Xc)
A daughter who has colorblindness (Xc)(Xc)
A son who is color blind (Xc)(Y)
A son who is not (XC)(Y).

front 19

Why are marriages between blood relatives prohibited in most cultures?

back 19

Because blook relatives have similar gene pools thus the likelihood of receiving a double-dose of recessive genes is increased.

front 20

What is the probability of having three daughters in a row?

back 20

The empirical probability is approximately 12.5%.
P(girl) = 0.5

Laws of probability dictate event (a) x (b) x (c)

= 0.5 x 0.5 x 0.5

=0.125

=12.5% chance