GEN CHEM CHP 4 MCAT REVIEW Flashcards Flashcards


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1

formula unit (FU)

formula unit (FU) - amount in of a certain molecule present in # of molecules

  • find by multiplying #moles x 6.023x10^23
2

molar mass M.M

molar mass M.M - mass 1 mol of a compound (g/mol)

  • p much straight from periodic table
3

molecular weight

molecular weight - amu/molecule (find amu)

4

equivalent

equivalent (n) - how much of certain thing is present?

  • ex: if have acid, like, H2SO4, will get 2 mols H+ (protons) for every 1 mol of the acid
  • n = 2

gram equivalent weight = molar mass/n

5

normality

normality (N) - concentration

  • equivalents/L

molarity = normality/n

6

law of constant composition

law of constant composition - any pure sample compound contains same elements in an identical mass ratio

7

empirical/molec. formulas

empirical formula - simplest whole number ratio of elements in compound

molecular formula - exact # atoms of each element in the compound as multiple of empirical formula

8

percent comp

percent composition = (mass element in formula/M.M.)x100

9

combination rxn

combination rxn - 2/more reactants forming 1 product

ex: 2H2 + O2 -> 2H2O

10

decomp rxn

decomposition rxncombination rxn - single reactant breaks down into 2/more products (heating, high frequency, radiation, electrolysis)

ex: 2HgO -> 2Hg + O2

11

combustion rxn

combustion rxn - involves fuel (hydrocarbon usually)) and oxidant (oxygen usually) -> usually form CO2 and H2O

CH4 + 2O2 -> CO2 + 2H2O

12

single displacement rxn

single displacement rxn - when atom/ion is replaced by atom/ion of another element

ex: Cu + AgNO3 -> Ag + CuNO3

13

double displacement rxn

double displacement rxn

look up example

14

neutralization rxns

neutralization rxns

15

balancing chem eq.

use stoichiometric coeffs to balance reactants/products. should have equal mols of everything

16

limiting/excess reagent

limiting reagent - whats used first

excess reagent - whats leftover in rxn

can find by comparing moles/grams used up by each reactant -> whichever makes less of the product is limiting. find excess by subtracting the amount used of the excess reactant in the limiting scenario from the starting amount of the excess reactant

17

percent yield

percent yield (%) = (actual/theoretical)x100